((3x+2)/(x^2+7x+12))

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Solution for ((3x+2)/(x^2+7x+12)) equation: 


D( x )

x^2+7*x+12 = 0

x^2+7*x+12 = 0

x^2+7*x+12 = 0

x^2+7*x+12 = 0

DELTA = 7^2-(1*4*12)

DELTA = 1

DELTA > 0

x = (1^(1/2)-7)/(1*2) or x = (-1^(1/2)-7)/(1*2)

x = -3 or x = -4

x in (-oo:-4) U (-4:-3) U (-3:+oo)

(3*x+2)/(x^2+7*x+12) = 0

x^2+7*x+12 = 0

x^2+7*x+12 = 0

DELTA = 7^2-(1*4*12)

DELTA = 1

DELTA > 0

x = (1^(1/2)-7)/(1*2) or x = (-1^(1/2)-7)/(1*2)

x = -3 or x = -4

(x+4)*(x+3) = 0

(3*x+2)/((x+4)*(x+3)) = 0

3*x+2 = 0 // - 2

3*x = -2 // : 3

x = -2/3

x = -2/3

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